Tim Drew Net Worth

Tim Drew is a Baseball Player who has an impressive net worth of $400 million. He was born in August 31, 1978 and is a right-handed pitcher who has played for the Cleveland Indians, Montreal Expos, and Atlanta Braves. He was named the Indians' 1999 Minor League Player of the Year, highlighting his impressive career.
Tim Drew is a member of Baseball Player

Age, Biography and Wiki

Birth Day August 31, 1978
Birth Place Georgia
Age 45 YEARS OLD
Birth Sign Virgo

💰 Net worth: $400 million (2024)

Tim Drew, a renowned baseball player hailing from Georgia, has accumulated a remarkable net worth of $400 million as estimated for the year 2024. With his extraordinary skills and passion for the sport, he has conquered the hearts of millions of fans worldwide. Throughout his successful career, Tim Drew has consistently displayed exceptional talent, earning numerous accolades and forging his path to greatness. His net worth stands as a testament to his dedication and hard work in the world of baseball, firmly establishing him as one of the wealthiest athletes in the industry.

About

Right-handed pitcher who played for the Cleveland Indians, Montreal Expos, and Atlanta Braves and was named Indians' 1999 Minor League Player of the Year.

Before Fame

He attended Lowndes County High School in Georgia.

Trivia

The Indians took him in the first round of the 1997 draft.

Family Life

His brothers J.D. and Stephen both won World Series with the Boston Red Sox, though they weren't teammates on the championship club.

Associated With

Versatile right-hander John Smoltz was his teammate on the Braves.